I gave a quick introduction to programming for my calculus class, which has been working on numerical integration.

Numerical integration is usually used for functions that can’t be integrated (or not easily integrated) but for this example we’ll use a simple parabolic function so we can compare the numerical results to the analytical solution (as seen here).

With the equation:

To find the area under the curve between *x = 1* and *x = 5* we’d find the definite integral:

which gives the result:

For numerical integration, we break the area of concern into a number of trapezoids, find the areas of all the trapezoids and add them up.

We’ll define the left and right boundaries of the area as * a* and

*, and we can write the integral as:*

**b**

We also have to choose a number of trapezoids (* n*) or the width of each trapezoid (

*). Here we choose four trapezoids (*

**dx***n = 4*), which gives a trapezoid width of one (

*dx = 1*).

So if we define the x values of the left and right sides of the first trapezoids as *x _{0}* and

*x*, the area of the first trapezoid is:

_{1}

For this program, we’ll set the trapezoid width (*dx*) and then calculate the number of trapezoids (*n*) based on the width and the locations of the end boundaries *a* and *b*. So:

and the sum of all the areas will be:

We can also figure out that since the x values change by the same value (dx) for every trapezoid, it’s an arithmetic progression, so:

and,

so our summation becomes:

Which we can program with:

*numerical_integration.py*

# the function to be integrated def func(x): return -0.25*x**2 + x + 4 # define variables a = 1. # left boundary of area b = 5. # right boundary of area dx = 1 # width of the trapezoids # calculate the number of trapezoids n = int((b - a) / dx) # define the variable for area Area = 0 # loop to calculate the area of each trapezoid and sum. for i in range(1, n+1): #the x locations of the left and right side of each trapezpoid x0 = a+(i-1)*dx x1 = a+i*dx #the area of each trapezoid Ai = dx * (func(x0) + func(x1))/ 2. # cumulatively sum the areas Area = Area + Ai #print out the result. print "Area = ", Area

And the output looks like

>>> Area = 17.5 >>>

While the programming is pretty straightforward, it was a bit of a pain getting Python to work for one of my students who is running Windows 8. I still have not figured out a way to get it to work properly, so I’m considering trying to do it using Javascript.

# Update

The javascript functions for numerical integration:

function numerically_integrate(a, b, dx, f) { // calculate the number of trapezoids n = (b - a) / dx; // define the variable for area Area = 0; //loop to calculate the area of each trapezoid and sum. for (i = 1; i <= n; i++) { //the x locations of the left and right side of each trapezpoid x0 = a + (i-1)*dx; x1 = a + i*dx; // the area of each trapezoid Ai = dx * (f(x0) + f(x1))/ 2.; // cumulatively sum the areas Area = Area + Ai } return Area; } //define function to be integrated function f(x){ return -0.25*Math.pow(x,2) + x + 4; } // define variables a = 1; // left boundary of area b = 5; // right boundary of area dx = 1; // width of the trapezoids // print out output alert("Area = "+ numerically_integrate(a, b, dx, f));

This is a demonstration of a full html file that uses the function, and should work in any modern browser (download files: numerical-integration.zip).

# Update 2

I've added the above javascript code to the embeddable graphs to allow it to calculate and display numerical integrals: you can change the values in the interactive graph below.

**Citing this post**: **Urbano**, L., 2013. Programming Numerical Integration with Python (and Javascript), Retrieved October 22nd, 2017, from *Montessori Muddle*: http://MontessoriMuddle.org/ .**Attribution (Curator's Code )**: Via: ᔥ Montessori Muddle; Hat tip: ↬ Montessori Muddle.